5(5)=y^2

Solution for 5(5)=y^2 equation:

5(5)=y^2

We move all terms to the left:

5(5)-(y^2)=0

We add all the numbers together, and all the variables

-1y^2+55=0

a = -1; b = 0; c = +55;
Δ = b2-4ac
Δ = 02-4·(-1)·55
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{55}}{2*-1}=\frac{0-2\sqrt{55}}{-2}
=-\frac{2\sqrt{55}}{-2}
=-\frac{\sqrt{55}}{-1}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{55}}{2*-1}=\frac{0+2\sqrt{55}}{-2}
=\frac{2\sqrt{55}}{-2}
=\frac{\sqrt{55}}{-1}
$